Solve for x ax-bx/x+c = d, if a =/b+d
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Answer:
dc/a-b-d
Step-by-step explanation:
ax – bx = d
x + c
Multiply both sides by x + c
ax – bx
(x + c) = d(x + c)
x + c
Simplify
ax – bx
(x+c): ax – bx
x + c
ax – bx = d(x+c)
Expand d(x+c): dx + cd
ax — bx = dx + cd
Subtract dx from both sides
ax – bx – dx = dx + cd – dx
Simplify
ax – bx – dx = cd
Factor ax – bx – dx: x(a – b – d)
x(a - b- d) = cd
Divide both sides by a – b – d; a + b + d
x(a – b - d) cd
a + b + d
a - b - d
a – b-d
Simplify
X =dc/a-b-d
The value of 'x' in the algebraic equation is [tex]\rm x= \frac{dc}{a-b-d} \\[/tex] where [tex]\rm a\neq b+d[/tex]
It is given that the algebraic equation [tex]\rm \frac{ax-bx}{x+c}= d[/tex]
It is required to solve the algebraic (polynomial) equation if [tex]\rm a\neq b+d[/tex]
Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.
We have an algebraic equation:
[tex]\rm \frac{ax-bx}{x+c}= d[/tex]
[tex]\rm \frac{ax-bx}{x+c}= d\\\\\rm ax-bx=d(x+c)\\\rm ax-bx=dx+dc\\\rm ax-bx-dx=dc\\\rm (a-b-d)x=dc\\\\\rm x= \frac{dc}{a-b-d} \\[/tex]
Thus, the value of 'x' in the algebraic equation is [tex]\rm x= \frac{dc}{a-b-d} \\[/tex] where [tex]\rm a\neq b+d[/tex]
Learn more about Polynomial here:
brainly.com/question/17822016