A man is jogging to work. From his house he runs 752 meters west, turns a corner and runs 587 meters south before arriving at work. What is the mans total distance covered AND net displacement (length of displacement and angle)?

Respuesta :

Answer:

[tex]d_t=1339m[/tex]

[tex]d_r=953.98[/tex]

[tex]x=37.975 \textdegree[/tex]

Explanation:

From the question we are told that

1st distance [tex]d_1=752 m[/tex]

2nd distance [tex]d_2=587 m[/tex]

Generally the total distance [tex]d_t[/tex]covered by the man is mathematically given as

[tex]d_t =1st\ distance +2nd\ distance[/tex]

[tex]d_t=752+587\\d_t=1339m[/tex]

Generally the resultant distance traveled is mathematically given as

[tex]d_r^2=d_1^2+d_2^2[/tex]

[tex]d_r=\sqrt{752^2+587^2}[/tex]

[tex]d_r=953.98[/tex]

Generally the angle  using sine rule traveled is mathematically given as

let angle =x

[tex]\frac{sin90}{d_r} =\frac{sinx}{587}[/tex]

[tex]sinx=\frac{sin90*587}{953.98}[/tex]

[tex]x=37.975 \textdegree[/tex]