Zinc metal reacts with aqueous copper(II) chloride, as shown in this equation. If 3.03 x 1021 atoms of zinc react, how many grams of Cu will form? Show the sequence of conversions necessary, then calculate the numerical answer. Zn (s) + CuCl2 (aq) ---> ZnCl2 (aq) + Cu (s)

Respuesta :

Answer:

0.320 g Cu.

Explanation:

Hello there!

In this case, case, according to the presented chemical reaction, it is possible to determine that the mole ratio of zinc to copper is 1:1 and therefore, we will have the same amount of atoms for the both of them. Moreover, since one mole of copper contains 6.022x10²³ atoms of this element, with a mass of 63.546 g (molar mass); it is possible for us to write up the following mathematical setup in order to calculate the produced grams of copper:

[tex]3.03x10^{21}atoms Zn*\frac{1atom Cu}{1atom Zn}*\frac{1molCu}{6.022x10^{23}atoms Cu}*\frac{63.546gCu}{1molCu} \\[/tex]

Thus, the numerical result turns out to be:

0.320 g Cu

Best regards!