HURRY!! WILL GIVE BRAINLIEST ANSWER!!

1. When aqueous solutions of lead(II) nitrate (Pb(NO3)2) and sulfuric acid
(H2SO4) react, lead(II) sulfate forms as a precipitate. Identify the spectator
ions and write a balanced net ionic equation for this reaction.

The ions Pb2+ and SO42- combine to form the precipitate.

Which two ions are spectator ions?

The net ionic reaction is Pb2+ + SO42...

HURRY WILL GIVE BRAINLIEST ANSWER 1 When aqueous solutions of leadII nitrate PbNO32 and sulfuric acid H2SO4 react leadII sulfate forms as a precipitate Identify class=

Respuesta :

The spectator ions would be the ions that don't comprise the precipitate in this reaction. You have four ionic species here: Pb²⁺, NO₃⁻, H⁺, and SO₄²⁻. Since Pb²⁺ and SO₄²⁻ combine, as you are told, to form the precipitate, that leaves H⁺ and NO₃⁻ (or, in normal text, H+ and NO3-) to be the spectator ions.

Edit: NO3- might be interpreted ambiguously since it's not immediately clear that the NO3 is a polyatomic ion with a -1 charge and not an NO compound with a 3- charge, so it should be written as [NO3]- or (NO3)-.

The net ionic reaction shows the reaction without the spectator ions. In this case, that would be: Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s).