katehalvor katehalvor

14-04-2021
Mathematics

contestada

How many solutions can be found for the equation 3z + 2[z - 3) = 7z+12

Respuesta :

ItzAdmire ItzAdmire

14-04-2021

Given :-

3z + 2(z - 3) = 7z + 12

Solution :-

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9

[tex] \\ [/tex]

Answered by - ItzAdmire

Answer Link

ItzMaster ItzMaster

14-04-2021

Given :-

3z + 2(z - 3) = 7z + 12

Solution :-

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9

[tex] \\ [/tex]

Answered by - ItzMaster

Answer Link

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