Answer: 16.3 L of ammonia gas can be formed from 24.5 L of hydrogen gas at STP
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
The balanced chemical equation is:
[tex]3H_2+N_2\rightarrow 2NH_3[/tex]
According to stoichiometry :
[tex]3\times 22.4=67.2L[/tex] of [tex]H_2[/tex] produce = [tex]2\times 22.4=44.8L[/tex] of [tex]NH_3[/tex] at STP
Thus 24.5 L of [tex]H_2[/tex] will produce= [tex]\frac{44.8}{67.2}\times 24.5=16.3L[/tex] of [tex]NH_3[/tex] at STP
Thus 16.3 L of ammonia gas can be formed from 24.5 L of hydrogen gas at STP
