Answer: First we need to know how many moles of each reactant there are.
C6H12O6 : 25g/180.06g/mol=0.1388mol
O2: 40g/32g/mol=1.25mol
The equation tells us we need 6 moles of O2 for every 1 mole of Glucose.
6 x 0.1388 = 0.8328
So, we have more O2 then needed – it is in excess.
Glucose is the limiting reagent – we use this for the calculation.
The equation tells us we make 6 moles of CO2 for every 1 mole of Glucose
So, we make 0,8328 moles of Carbon Dioxide
Explanation: