A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. You scored a 625. Calculate your z-score to the nearest hundredth (i.e. 2 decimal places).

z=

Given: A college-entrance exam is designed so that scores are normally distributed with a mean[tex](\mu)[/tex] = 500 and a standard deviation[tex](\sigma)[/tex] = 100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = [tex]\dfrac{Y-\mu}{\sigma}[/tex]

Z-score = [tex]\dfrac{625-500}{100}[/tex]

⇒ Z-score = [tex]\dfrac{125}{100}[/tex]

⇒Z-score =1.25

Therefore , the required z-score = 1.25

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. You scored a 625. Calculate your z-score to the nearest hundredth (i.e. 2 decimal places). z=

Respuesta :

Otras preguntas

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. You scored a 625. Calculate your z-score to the nearest hundredth (i.e. 2 decimal places).

z=