What can you say about the end behavior of the function f(x) = -4x6+6x2 -52 ?
A. F(x)is an even function so both ends of the graph go in the same
direction.
B. f(x) is an even function so both ends of the graph go in opposite
directions
O C. The leading coefficient is negative so the left end of the graph
goes up.
D. The leading coefficient is negative so the left end of the graph
goes down

What can you say about the end behavior of the function fx 4x66x2 52 A Fxis an even function so both ends of the graph go in the same direction B fx is an even class=

Respuesta :

Answer:

A. F(x)is an even function so both ends of the graph go in the same direction.

D. The leading coefficient is negative so the left end of the graph goes down.

Step-by-step explanation:

Even function:

For every value of x, f(x) = f(-x)

In this question:

We are given the following function:

[tex]f(x) = -4x^6 + 6x^2 - 52[/tex]

Testing if it is even:

[tex]f(1) = -4(1)^6 + 6(1)^2 - 52 = -4 + 6 - 52 = -50[/tex]

[tex]f(-1) = -4(-1)^6 + 6(-1)^2 - 52 = -4 + 6 - 52 = -50[/tex]

Since f(1) = f(-1), it is even.

Since it is even, both ends of the graph go in the same direction, so option A is correct, while option B is wrong.

Options C and D:

The leading coefficient, is -4(which multiplies x with the highest exponent). Since it is negative, it goes to negative infinity as x increases, that is, the left end goes down, and option D is correct while C is not.