A group of Americans participated in a study that involved taking their temperatures during exercise in extreme heat. The participants had a mean body temperature of 104^{\circ} \text{F}104 ∘ F104, degrees, start text, F, end text and a standard deviation of 2^{\circ} \text{F}2 ∘ F2, degrees, start text, F, end text. Doctors analyzing the results prefer to work in degrees Celsius, so they convert the data by applying the formula below to each data point: ^{\circ}\text{C}=\dfrac59(^{\circ}\text{F}-32) ∘ C= 9 5 ​ ( ∘ F−32)degrees, start text, C, end text, equals, start fraction, 5, divided by, 9, end fraction, left parenthesis, degrees, start text, F, end text, minus, 32, right parenthesis If each temperature is converted to degrees Celsius, what will be the mean and standard deviation of the distribution of new temperatures?

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Answer:

the mean is 40 degrees celcius

standar deviaton is 1.11 degrees Celsius

Step-by-step explanation

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The temperature values of the participants in celcius are :

  • Mean = 40°C
  • Standard deviation = - 16.67°C

Information about body temperature :

Mean = 104°F

Standard deviation = 2°F

To convert to Celsius temperature :

°C = 5/9(°F - 32)

To temperature values in °C :

Mean temperature :

°C = 5/9(104 - 32)

°C = 40°C

Standard deviation of temperature :

°C = 5/9(2 - 32)

°C = - 16.67°C

Hence, the temperature values in Celcius are : 40°C and - 16.67°C

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