Integer Quotient Problem
Two positive integers have a sum of 92.
If the larger integer is divided by the smaller one, the quotient is 3
and the remainder is 12. What are the two integers?

Respuesta :

Suppose that we have x and y as the integers( x is bigger than y ).

As the question told :

x = 3y + 12

_________________________________The integers have a sum of 92 which means :

x + y = 92 ==》( 3y + 12 ) + y = 92

==》 4y + 12 = 92

==》 4y = 92 - 12

==》 4y = 80

==》 y = 20

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x + y = 92 ==》x + 20 = 92

==》x = 92 - 20

==》x = 72

Answer:

The two integer is, y = 20 and

                               x = 72

Step-by-step explanation:

Definition of integer:

Integer, positive or negative whole number, or 0 The integers are created using the counting numbers 1, 2, 3,... and the subtraction function. The result of subtracting a counting number from itself is zero; for example, 4 4 = 0. When you subtract a greater number from a smaller number, you get a negative whole number; for example, 2 3 = 1. Every integer may be deduced from the counting numbers in this fashion, resulting in a set of numbers that can be subtracted.

As the question told :

x = 3y + 12

The integers have a sum of 92 which means :

x + y = 92

        = ( 3y + 12 ) + y = 92

        = 4y + 12 = 92

        =  4y = 92 - 12

        =  4y = 80

     y = 20

Then, x + y = 92

       x + 20 = 92

                x = 92 - 20

                x = 72

The two integer is, y = 20 and x = 72

To know abour integer here, https://brainly.com/question/17695139  

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