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Swapna gathered data on the number of page views for each of her blog posts. For her 40 latest posts, she found a sample mean of 358 with a population standard deviation of 54.3. What is the approximate 95% confidence interval for her page views? HINT: It's not D.

A. 344 and 372
B. 356 and 360
C. 341 and 375
D. 336 and 380

Swapna gathered data on the number of page views for each of her blog posts For her 40 latest posts she found a sample mean of 358 with a population standard de class=

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Answer: for plato users

D. 341  and 375

Step-by-step explanation:

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The approximate 95% confidence interval for Swapna's page views is [341, 375].

What is confidence interval?

  • It is a range of values that's likely to include a population value with a certain degree of confidence.
  • It is expressed as a percent (%) where a population mean lies between an upper and lower interval.
  • A confidence interval is how much uncertainty is with any particular statistic.
  • When it is a 95% confidence interval, it means a range of values that you can be 95% certain contains the true mean of the population.
  • A confidence interval is obtained from the observed data that holds the actual value of the unknown parameter.

Formula of confidence interval:

Confidence interval =  mean ± Z * (standard deviation/ √sample size)

For given question,

Sample size = 40

Sample mean = 358

Standard deviation = 54.3

Critical value at 95% confidence level= 1.96

Confidence interval = 358 ± 1.96 * (54.3/ √40)

                                  = [358 - 1.96 * (54.3/ √40) ,358 + 1.96 * (54.3/ √40)]

                                  = [341, 375] (approximately)

Learn more about confidence interval here

https://brainly.com/question/24131141

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