Step-by-step explanation:
Given that,
The area of the square base, A = 36 cm²
Slant height, s = 12 cm
We need to find the lateral area of the regular pyramid. The formula is :
[tex]S=A+\dfrac{1}{2}p\times s[/tex]
Where
A is the area of base
p is perimeter of base
s is slant height
Area of square, A = side²
So,
[tex]side=6\ cm[/tex]
Put values in the above formula.
[tex]S=36+\dfrac{1}{2}\times 4\times 6\times 12\\\\=36+144\\\\=180[/tex]
So, the lateral area of the regular pyramid is equal to 180 cm².
