Write the exact value of the side length of a square whose are in square units are given. For example, use sqrt(9) to represent the square root of 9. Areas: 36 37 100/9 2/5 0.0001 0.11

Respuesta :

Answer:

a.) Side length of the square is 6 units.

b.) Side length of the square is sqrt(37) units.

c.) Side length of the square is 10/3 units.

d.) Side length of the square is sqrt(2/5) units.

e.) Side length of the square is 0.01 units.

f.) Side length of the square is sqrt(11)/10 units.

Step-by-step explanation:

To find - Write the exact value of the side length of a square whose are in square units are given

a) 36

b) 37

c) 100/9

d) 2/5

e) 0.0001

f) 0.11

Proof -

We know that ,

If a is the side length of the square then,

Area of square = a²

Now,

a) 36

⇒a² = 36

⇒a² = (6)²

⇒a = 6

∴ we get

Side length of the square is 6 units.

b.) 37

⇒a² = 37

⇒a² = [sqrt(37)]²

⇒a = sqrt(37)

∴ we get

Side length of the square is sqrt(37) units.

c.)100/9

⇒a² = 100/9

⇒a² = [10/3]²

⇒a = 10/3

∴ we get

Side length of the square is 10/3 units.

d.)2/5

⇒a² = 2/5

⇒a² = [sqrt(2/5)]²

⇒a = sqrt(2/5)

∴ we get

Side length of the square is sqrt(2/5) units.

e.)0.0001

⇒a² = 0.0001

⇒a² = [0.01]²

⇒a = 0.01

∴ we get

Side length of the square is 0.01 units.

f.)0.11

⇒a² = 0.11

⇒a² = [sqrt(11)/10]²

⇒a = sqrt(11)/10

∴ we get

Side length of the square is sqrt(11)/10 units.

We get the value of the,

a.) Side length of the square is 6 units.

b.) Side length of the square is sqrt(37) units.

c.) Side length of the square is 10/3 units.

d.) Side length of the square is sqrt(2/5) units.

e.) Side length of the square is 0.01 units.

f.) Side length of the square is sqrt(11)/10 units.

We have to find the exact value of the side length of a square whose are in square units are given

a) 36

b) 37

c) 100/9

d) 2/5

e) 0.0001

f) 0.11

We have given that,sqrt(9) to represent the square root of 9.

We know that ,

If a is the side length of the square then,

what area of the square?

Area of square = a²

For option a) 36

⇒a² = 36

⇒a² = (6)²

⇒a = 6

∴ we get side length of the square is 6 units.

For the option b is  37.

⇒a² = 37

⇒[tex]a^2 = \sqrt{37} ^2[/tex]

⇒[tex]a = sqrt(37)[/tex]

∴ we get side length of the square is  [tex]\sqrt(37)[/tex]  units.

c.)100/9

⇒[tex]a^2 = 100/9[/tex]

⇒[tex]a^2= [10/3]^2[/tex]

⇒[tex]a = 10/3[/tex]

∴ we get side length of the square is 10/3 units.

for the option d.)2/5

[tex]a^2= 2/5[/tex]

[tex]a^2 = [\sqrt(2/5)]^2[/tex]

⇒[tex]a = \sqrt(2/5)[/tex]

∴ we get side length of the square is [tex]\sqrt(2/5)[/tex]units.

for the option e.)0.0001

[tex]a^2 = 0.0001[/tex]

[tex]a^2 = [0.01]^2[/tex]

[tex]a = 0.01[/tex]

∴ we get side length of the square is 0.01 units.

For option f.)0.11

⇒[tex]a^2 = 0.11[/tex]

⇒[tex]a^2= [\sqrt(11)/10]^2[/tex]

[tex]a = \sqrt(11)/10[/tex]

∴ we get side length of the square is[tex]\sqrt(11)/10[/tex] units.

Therefore we get,we get the value of the,

a.) Side length of the square is 6 units.

b.) Side length of the square is sqrt(37) units.

c.) Side length of the square is 10/3 units.

d.) Side length of the square is sqrt(2/5) units.

e.) Side length of the square is 0.01 units.

f.) Side length of the square is sqrt(11)/10 units.

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