Respuesta :

The original area is:
+8.5%2A11+=+93.5+ in2
There are 4 corners, so
+4%2A2+=+8+ in2 total removed
+93.5+-+8+=+85.5+
The new area is 85.5 in2
HealingPearl

Given Information :

  • Dimensions of the sheet = 8.5 in x 11 in
  • 2 in[tex] \sf ^2 [/tex] has been cut from each corner of the sheet.

To calculate :

  • Area of the sheet.

Calculation :

Area of the sheet when 2 in[tex] \sf ^2 [/tex] hasn't been cut from each corner of the sheet :-

→ Area = Length × Breadth

→ Area = ( 8.5 × 11 ) in[tex] \sf ^2 [/tex]

→ Area = 93.5 in[tex] \sf ^2 [/tex]

Area of the part cut from it :

  • 2 in[tex] \sf ^2 [/tex] has been cut from each corner of the sheet. [ A sheet has 4 corners. ]

→ ( 4 × 2 ) in[tex] \sf ^2 [/tex]

→ 8 in[tex] \sf ^2 [/tex]

Remaining area :

→ Remaining area = 93.5 in[tex] \sf ^2 [/tex] - 8 in[tex] \sf ^2 [/tex]

→ Remaining area = 85.5 in[tex] \sf ^2 [/tex]

Therefore,

  • The area of the sheet of paper will be 85.5 in[tex] \sf ^2 [/tex]

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