Answer: 11.02 moles of Ag can be formed.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} Cu=\frac{350.00g}{63.55g/mol}=5.51moles[/tex]
The balanced chemical equation is:
[tex]Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag[/tex]
According to stoichiometry :
1 moles of [tex]Cu[/tex] produces = 2 moles of [tex]Ag[/tex]
Thus 5.51 moles of [tex]Cu[/tex] will produce=[tex]\frac{2}{1}\times 5.51=11.02moles[/tex] of [tex]Ag[/tex]
Thus 11.02 moles of Ag can be formed.
