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Answer:

Simplified expression: [tex]\frac{1}{y+8 }[/tex].

The value of y that makes the expression undefined is y=-8.

Step-by-step explanation:

[tex]\frac{2y^{3}}{2y^{4}+16y^{3}}[/tex]

= [tex]\frac{2y^{3}}{2y^{3}(y+8) }[/tex]

(cancel out 2y³)

=[tex]\frac{1}{y+8 }[/tex]

A rational expression is undefined when the denominator (bottom number) is  zero. So, if y equalled -8, the expression would ultimately equal [tex]\frac{1}{0}[/tex], which is undefined.