Answer: The molality of solution is 1.2 mole/kg
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
[tex]Molality=\frac{n}{W_s}[/tex]
where,
n = moles of solute
[tex]W_s[/tex] = weight of solvent in kg
Given : 10 g of glycerol is present in 100 g of solution
moles of glycerol = [tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{10g}{92g/mol}=0.108mol[/tex]
mass of water (solvent )= (100-10) = 90 g = 0.09 kg
Now put all the given values in the formula of molality, we get
[tex]Molality=\frac{0.108mol}{0.09kg}=1.2mole/kg[/tex]
Therefore, the molality of solution is 1.2 mole/kg
