Aiden invested $98,000 in an account paying an interest rate of 2 % compounded
continuously. Autumn invested $98,000 in an account paying an interest rate of 2%
compounded quarterly. After 11 years, how much more money would Autumn have in
her account than Aiden, to the nearest dollar?

Respuesta :

Answer:

Aiden would have $67 more than Autumn.

Step-by-step explanation:

Aiden compounded continuously, which uses the formula: [tex]P(t)=P_oe^r^t[/tex]

Plugging in what we know about Aiden's investment: [tex]P(11)=98000e^0^.^0^2^*^1^1[/tex]

That gives us: 122115.5196

Autumn invested using regular compound interest, which has the formula: [tex]A=P(1+\frac{r}{t})^n^t[/tex]

Since Autumn's investment is getting compounded quarterly, n=4 because it gets compounded 4 times a year.

Plug in Autumn's investment: [tex]A=98000(1+\frac{0.02}{4})^4^*^1^1[/tex]

That gives us: 122048.5974

Now just subtract the two and round to the nearest dollar:

[tex]122115.5196-122048.5974=66.92215187[/tex]

OR

$67. Aiden would have $67 more than Autumn after 11 years.