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A gas that exerts a pressure of
15.6 psi in a container with a volume of
L will exert a pressure of
25.43 psi when transferred to a
container with a volume of 1.895 L.

Respuesta :

ajeigbeibraheem

Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

[tex]P_1[/tex] = 15.6 psi

[tex]V_1[/tex] = ???

[tex]P_2[/tex] = 25.43 psi

[tex]V_2[/tex] = 1.895 L

Using Boyle's law:

[tex]P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\ V_1 = \dfrac{25.43 \times 1.895}{15.6} \\ \\ \mathbf{ V_1 = 3.089 \ L}[/tex]

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