Answer:
d = 5[tex]\sqrt{2}[/tex] + 5[tex]\sqrt{2}[/tex] = 10 [tex]\sqrt{2}[/tex]
Step-by-step explanation:
A = πr²
50π = πr²
50 = r²
[tex]\sqrt{50}[/tex] = r
[tex]\sqrt{25}[/tex]· [tex]\sqrt{2}[/tex] = radius
2(5[tex]\sqrt{2}[/tex]) = diameter
10[tex]\sqrt{2}[/tex] = diameter
