Answer:
The right answer is "5.9". A further solving is provided below.
Step-by-step explanation:
The given values are:
Initial Magnitude,
M₁ = 3.9
Let Second magnitude be M₂.
Now,
⇒ [tex]M_2-M_1=log(\frac{l_2}{l_1} )[/tex]
On substituting the values, we get
⇒ [tex]M_2-3.9 = log (120)[/tex]
On putting the value of "log 120", we get
⇒ [tex]M_2-3.9=2.079[/tex]
On adding "3.9" both sides, we get
⇒ [tex]M_2-3.9+3.9=2.079+3.9[/tex]
⇒ [tex]M_2=5.9[/tex]
