Respuesta :
The net force on particle q2 is 21.7 N.
The given parameters:
- Charge on particle 1, q1 = 8 μC
- Charge on particle 2, q2 = 3.5 μC
- Charge on particle 3, q3 = -2.5 μC
- Distance between particle 1 and particle 2 = 0.1 m
- Distance between particle 2 and particle 3, = 0.15 m
The net force on particle q2 is calculated as follows;
[tex]Q_2_{net} = q_{12} \ + \ q_{23}\\\\Q_2_{net} = \frac{kq_1q_2}{r_{12} ^2} \ + \ \frac{kq_2q_3}{r_{23}^2} \\\\Q_2_{net} = \frac{9\times 10^9 \times 8 \times 10^{-6} \times 3.5 \times 10^{-6} }{0.1^2} \ + \ \frac{9 \times 10^9 b\times 3.5 \times 10^{-6} \times (-2.5) \times 10^{-6} }{0.15^2} \\\\Q_2_{net} = 25.2 \ N \ - \ 3.5 \ N\\\\Q_2_{net} = 21.7 \ N[/tex]
Thus, the net force on particle q2 is 21.7 N.
Learn more about Coulomb's law here: https://brainly.com/question/24743340