Answer: 2.67 m/s
Explanation:
Given
Mass of block A is [tex]m_a=2\ kg[/tex]
mass of block B is [tex]m_b=3\ kg[/tex]
The initial velocity of block A [tex]u_a=5\ m/s[/tex]
the initial velocity of block B is [tex]u_b=0[/tex]
After collision velocity of block A is [tex]v_a=1\ m/s[/tex]
Conserving momentum
[tex]m_au_a+m_bu_b=m_av_a+m_bv_b\\\\2\times 5+3\times0=2\times 1+3\times v_b\\\\v_b=\dfrac{8}{3}=2.67\ m/s[/tex]
The momentum of block A after the collision is [tex]P_a=2\times 1=2\ kg.m/s[/tex]
Therefore, there is no change in sign.
