Answer:
Following are the responses to the given question:
Step-by-step explanation:
[tex]\angle C= 180 - ( 26 + 51 )\\\\C = 103^{\circ}[/tex]
applying the law of sines to find the unknown sides:
[tex]\to \frac{a}{\sin A} = \frac{c}{\sin C}\\\\\to \frac{a}{\sin 26} = \frac{28}{\sin 103}\\\\a=\frac{28 \times \sin 26 }{\sin 103}\\\\a=\frac{28 \times 0.438371147 }{0.974370065}\\\\a=\frac{12.2743921 }{0.974370065}\\\\a=12.597259\\\\a=12.59\\\\a = 12.6 \ m\\\\[/tex]
[tex]\to \frac{b}{\sin 51} = \frac{28}{\sin 103}\\\\\to b=\frac{28 \times \sin 51 }{\sin 103}\\\\b=\frac{28 \times 0.777145961 }{0.974370065}\\\\b=\frac{21.7600869 }{0.974370065}\\\\b=22.3324681\\\\b=22.3\\\\b = 22.3 \ m\\\\[/tex]
so,
[tex]\angle C = 103^{\circ}\\\\\to AC = 22.3\ m\\\\\\to BC = 12.6 \ m[/tex]
