Answer:
p = 923.2 millibar
Step-by-step explanation:
Given that,
The wind velocity can be described by the function as follows :
[tex]v(p)=5.7\sqrt{998-p}[/tex]
Where
p is the air pressure in millibar
Put v = 49.3 m/s in the above function.
[tex]49.3=5.7\sqrt{998-p}[/tex]
Squaring both sides,
[tex]49.3^2=(5.7\sqrt{998-p})^2\\\\2430.49=32.49(998-p)\\\\\dfrac{2430.49}{32.49}=(998-p)\\\\74.80=(998-p)\\\\p=998-74.80\\\\p=923.2\ mbar[/tex]
So, the required pressure is equal to 923.2 millibar.
