2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explain each step in figuring out how to determine the time it would

take Jennifer to complete this job on her own. Pls help 20 minutes left

Respuesta :

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

[tex]\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}[/tex]

[tex]\frac{1}{4} = \frac{15 + x + x}{x(15+x)}[/tex]

[tex]\frac{1}{4} = \frac{15 + 2x}{x(15+x)}[/tex]

Applying cross multiplication.

[tex]x^2 + 15x = 4(15 + 2x)[/tex]

[tex]x^2 + 15x = 60 + 8x[/tex]

[tex]x^2 + 7x - 60 = 0[/tex]

Quadratic equation with [tex]a = 1, b = 7, c = -60[/tex]. So

[tex]\Delta = 7^{2} - 4*1*60 = 289[/tex]

[tex]x_{1} = \frac{-7 + \sqrt{289}}{2} = 5[/tex]

[tex]x_{2} = \frac{-7 - \sqrt{289}}{2} = -12[/tex]

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.