Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
The slope of the lines is the same, the line segments FG and EH are parallel to each other and are the opposite sides of the quadrilateral.
A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,
y =mx + c
where,
x is the coordinate of the x-axis,
y is the coordinate of the y-axis,
m is the slope of the line, and
c is constant.
The slope of the line segment FG can be found by comparing the equation with the equation of the line. Therefore,
y = mx + c
-2 = 3x - y
- 2 - 3x = -y
y = 3x + 2
Thus, the slope of the equation is 3.
The slope of the line segment EH can be found by comparing the equation with the equation of the line. Therefore,
y = mx + c
3x - y = -6
-y = 6 - 3x
y = 3x+6
Thus, the slope of the equation is 3.
Since the slope of the lines is the same, the line segments FG and EH are parallel to each other and are the opposite sides of the quadrilateral.
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