Answer:
Height of the Foshay tower is 138 m
Explanation:
Using the third equation of uniformly-accelerated motion under gravity:
v² = u² + 2gh
Where v is final velocity,
u is initial velocity,
g is acceleration due to gravity,
and h is height
v = 52 m/s;
u = 0 (since the marble was dropped from rest at a height above the ground);
g = 9.8 m/s²,
h = ?
(52 m/s)² = 0 + 2 × 9.8 m/s² × h
2704 m²/s² = 19.6 m/s² × h
h = 2704 m²/s² / 19.6 m/s²
h = 138 m
Therefore, height of the Foshay tower is 138 m
