Respuesta :
Answer: [tex]Fe^{3+} > Mn^{4+}[/tex] > [tex]V^{3+}[/tex] = [tex]Ni^{2+}[/tex] > [tex]Cu^+[/tex]
Explanation:
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.
Fe: 26: [tex]1s^2s^22p^63s^23p^64s^23d^{6}[/tex]
[tex]Fe^{3+}:23:1s^2s^22p^63s^23p^63d^{5}[/tex] : 5 unpaired electrons
Mn: 25: [tex]1s^2s^22p^63s^23p^64s^23d^{5}[/tex]
[tex]Mn^{4+}:23:1s^2s^22p^63s^23p^63d^{3}[/tex] : 3 unpaired electrons
V: 23: [tex]1s^2s^22p^63s^23p^64s^23d^{3}[/tex]
[tex]V^{3+}:23:1s^2s^22p^63s^23p^63d^{2}[/tex] : 2 unpaired electrons
Ni : 28 : [tex]1s^2s^22p^63s^23p^64s^23d^{8}[/tex]
[tex]Ni^{2+}:23:1s^2s^22p^63s^23p^63d^{8}[/tex]: 2 unpiared electrons
Cu : 29 : [tex]1s^2s^22p^63s^23p^64s^13d^{10}[/tex]
[tex]Cu^{+}:23:1s^2s^22p^63s^23p^63d^{10}[/tex]: 0 unpaired electrons
Thus the order of decreasing number of unpaired electrons:
[tex]Fe^{3+} > Mn^{4+}[/tex] > [tex]V^{3+}[/tex] = [tex]Ni^{2+}[/tex] > [tex]Cu^+[/tex]
