Respuesta :
Answer: The maximum amount of water that can be produced is 0.74 g
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Putting values in equation 1, we get:
[tex]\text{Moles of hydrochloric acid:}=\frac{1.5g}{36.5g/mol}=0.041mol[/tex]
[tex]\text{Moles of sodium hydroxide}=\frac{2.67g}{40g/mol}=0.067mol[/tex]
The chemical equation for the reaction is
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of HCl reacts with 1 mole of NaOH
So, 0.041 moles of HCl will react with = [tex]\frac{1}{1}\times 0.041=0.041mol[/tex] of NaOH
As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent. Thus, HCl is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of HCl produces = 1 mole of water
So, 0.041 moles of HCl will produce = [tex]\frac{1}{1}\times 0.041=0.041moles[/tex] of water
Mass of water=[tex]moles\times {\text{Molar Mass}}=0.041mol\times 18g/mol=0.74g[/tex]
Thus the maximum amount of water that can be produced is 0.74 g
