Answer:
[tex]\dfrac{dE}{dt} \approx 2.261 \overline {36} \times 10^{12} \ V/ms[/tex]
Explanation:
The parameters given in the question are;
The magnitude of the displacement current density between the plates of a parallel-plate capacitor, J = 19.9 A/m²
We have;
[tex]i_d = \epsilon _0 \times \dfrac{d \Phi_E}{dt} =\epsilon _0 \times A \times \dfrac{d E}{dt}[/tex]
Therefore;
[tex]\therefore \dfrac{dE}{dt} =\dfrac{i_d}{\epsilon _0 \cdot A} =\dfrac{J}{\epsilon_0} = \dfrac{19.9}{8.8 \times 10^{-12}} \approx 2.261 \overline {36} \times 10^{12}[/tex]
Therefore;
[tex]\therefore \dfrac{dE}{dt} \approx 2.261 \overline {36} \times 10^{12} \ V/ms[/tex]
