Answer:
r=0.179 or r =[tex]\sqrt[3]{5.7296}[/tex]
Step-by-step explanation:
Hello!
The volume of a sphere equation is:
V = 4π/3 r³
The question asking, what is the radius that has a volume of 24pi. We should now rearrange the volume of a sphere equation to isolate r.
V = [tex]\frac{4\pi }{3\ r^{3} }[/tex]
[tex]\frac{1}{V} = \frac{3r^{3} }{4\pi }[/tex]
[tex]\frac{3V }{4\pi } =r^{3}[/tex]
r = [tex]\sqrt[3]{\frac{3V}{4\pi } }[/tex]
r = [tex]\sqrt[3]{\frac{3*24}{4\pi } }[/tex]
r = about 1.79
Hope this helps!
