Respuesta :
Answer:
0% probability that the selected time is exactly 1.2 seconds.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The probability of a value being equals to x is 0 in the normal distribution.
From a ten-year-old study, the mean time between mating calls was 1.2 seconds with a standard deviation of .3 seconds.
This means that [tex]\mu = 1.2, \sigma = 0.3[/tex]
Calculate the probability that the selected time is exactly 1.2 seconds?
In the normal distribution, the probability of a finding an exact value is 0. So 0% probability that the selected time is exactly 1.2 seconds.
