marshallfcc8
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What is the electrical force between 91 and 92? Recall
that k = 8.99 * 109 Nom?
2 m
9, +6 C
9,=-40
+1 m +
O 4.3 x 1010 N
q = +3 C O 3,5 x 1010 N
O -5.4 x 1010 N
O -5.8 x 10101

What is the electrical force between 91 and 92 Recall that k 899 109 Nom 2 m 9 6 C 940 1 m O 43 x 1010 N q 3 C O 35 x 1010 N O 54 x 1010 N O 58 x 10101 class=

Respuesta :

hamzaahmeds

Answer:

F = 5.39 x 10¹⁰ N

Explanation:

The electrical force between q₁ and q₂ can be calculated by Coulomb's Law:

[tex]F = \frac{kq_1q_2}{r^2}\\\\[/tex]

where,

F = electrical force = ?

k = Coulomb Constant = 8.99 x 10⁹ Nm²/C²

q₁ = first charge = +6 C = 6 C

q₂ = -4 C = 4 C

r = distance between charges = 2 m

Therefore,

[tex]F = \frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ C)(4\ C)}{(2\ m)^2}\\\\[/tex]

F = 5.39 x 10¹⁰ N

aaliyahanniebiella

Answer:

C on edge

Edge2021

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