Respuesta :

Answer:

22

Step-by-step explanation:

222

The value of k in the given functions is; 24

What is the value of the function to the tangent?

We are given the functions;

g(x) = 4x  + k as a tangent to f(x) = -x² +8x +20

For f(x) = -x² +8x +20

=> f'(x)  = -2x + 8

Thus, slope of tangent at ( x , y) = -2x + 8  

For g(x) = 4x  + k

g'(x) = 4.

Thus, slope is 4

Therefore;

-2x  + 8 = 4

-2x = -4

x = 2

Putting 2 for x in f(x) gives;

f(2) = -2² + 8(2) + 20  

f(2) =  32

Thus, it is at (2 , 32)

Thus, (2 , 32) lies on g(x) = 4x + k

4(2) + k = 32

k = 32 - 8

k = 24

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