Could someone help me, please?
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Answer:
33°
Step-by-step explanation:
<ACD =90-33 =57°
<DCB=<ACB - <ACD
=90° -57 =33°
In triangle ACD the only angle that has not been found is <ACD so you find it by adding 90+33 and subtracting from 180° to get 57°. <ACB =90° and <ACD = 57° ,the angle in question is<DCB which is part of< ACB. So to get <DCB you do 90°-57°=33°.
B = 180 - 90 - 33 = 57°
C in DCB tringle = 180 - 90 - 57 = 33°
So C in DCB triangle = 33°