Answer:
solution
given,
mass(m)=5040kg
kinetic energy(ke)=493,900
velocity(v)=?
[tex]ke = \frac{1}{2} mv {}^{2} \\ 493900 = \frac{1}{2} \times 5040 \times v {}^{2} \\ 493900 = \frac{5040v {}^{2} }{2} \\ 493900 = 2520v {}^{2} \\ v {}^{2} = 196 \\ v = \sqrt{196} \\ v = 14ms {}^{ - 1} [/tex]
When an object moves from one point to other point, it possess the energy which is called the Kinetic energy of the object.
The velocity of he bus is 14 m/s.
Given that, a bus travelling through town, with a mass of 5040 kg and kinetic energy of 493,900 J.
So the kinetic energy expressed by the formula given below.
[tex]k=\dfrac {1} {2}mv^2[/tex]
Where, [tex]k[/tex] is the kinetic energy in joules, [tex]m[/tex] is the mass of object in kilograms and [tex]v[/tex] is the velocity of the object in meter per second.
So the velocity of the bus can be calculated by substituting the values in above formula.
[tex]493900=\dfrac{1}{2}\times5040\times v^2[/tex]
[tex]v^2=196\\\\v=\sqrt{196}\\v=14\;\rm m/s[/tex]
The velocity of he bus is 14 m/s.
For more details, follow the link given below.
https://brainly.com/question/999862.
