Answer: The initial volume of gas was [tex]282cm^3[/tex]
Explanation:
Charles's Law: This law states that volume is directly proportional to temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas =?
[tex]V_2[/tex] = final volume of gas = [tex]212cm^3[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]122.0^0F=323.15K[/tex]
[tex](32^0C=273.15K)[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-23.0^0F=242.59K[/tex]
[tex]\frac{V_1}{323.15}=\frac{212}{242.59}[/tex]
[tex]V_2=282cm^3[/tex]
Therefore, the initial volume of gas was [tex]282cm^3[/tex]
