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Situation: Find the substance's half-life, in days. Round your answer to the nearest tenth. A 50 gram sample of a substance that's used to treat thyroid disorders has a k- value of 0.1133. Enter the correct answer. N = Noe -kt DONE No = initial mass (at time t = 0) 1? N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days
Find the substance's half-life , in days.
Round your answer to the nearest tenth.​

Respuesta :

whitneytr12

Answer:

The substance's half-life is 6.1 days.

Step-by-step explanation:

The half-life of the substance can be calculated by knowing the constant decay:  

[tex] t_{1/2} = \frac{ln(2)}{k} [/tex]                          

k: is the decay constant = 0.1133 d⁻¹

Hence, the half-life is:      

[tex] t_{1/2} = \frac{ln(2)}{k} = \frac{ln(2)}{0.1133 d^{-1}} = 6.1 d [/tex]

Therefore, the substance's half-life is 6.1 days.

I hope it helps you!          

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