Respuesta :

Answer: Since this is the right triangle so

[tex]Sin B = \frac{AC}{AB} =\frac{AC}{6} \\=> AC = sin(20) * 6 = 5.478 = 5.48[/tex]

Apply Pythagorean theorem:

[tex]AC^{2} +CB^{2} =AB^{2} \\5.48^{2} +CB^{2} =6^{2}[/tex]

[tex]CB = \sqrt{6^{2} -5.48^{2} } = 2.44[/tex]