Two planes, which are 2920 miles apart, fly toward each other. Their speeds differ by 80mph. If they pass each other in 4 hours, what is the speed of each?

Respuesta :

9514 1404 393

Answer:

  405 mph; 325 mph

Step-by-step explanation:

The total of their speeds is ...

  2920 mi/(4 h) = 730 mi/h

If s represents the speed of the slower plane, then we have ...

  s + (s+80) = 730

  2s = 650 . . . . . . .  subtract 80

  s = 325 . . . . . . . divide by 2

  s+80 = 405 . . .  find the faster speed

The speeds of the planes are 405 mi/h and 325 mi/h.