A bag contains 4 white balls, 6 yellow balls, and 5 red balls. In how many ways can 6 balls be chosen if there must be 2 balls of each color? Which of the following combination notation will best represent the problem? Help!

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Answer:

4C2 * 6C2 * 5C2

Step-by-step explanation:

White balls = 4

Yellow balls = 6

Red balls = 5

In other to select a total of 6 balls, of which there must be 2 balls each of color white, yellow and red :

That means :

2 red balls from 5 red balls = 5C2

2 balls for 6 yellow balls = 6C2

2 balls from 4 white balls = 4C2

To obtain the number of possible combinations, take the product of the three combinations :

4C2 * 6C2 * 5C2

If bag contains 4 white balls, 6 yellow balls, and 5 red balls then  6 balls can be chosen if there must be 2 balls of each color in 900 ways

What are permutation and combination?

permutation is way of selecting and arranging things while combination is way of selecting things .

Given that  bag contains 4 white balls, 6 yellow balls, and 5 red balls

we have to select 6 balls

it's given that there must be 2 balls of each color

So here's how we can select them

2 white balls ,2 yellow balls and 2 red balls

So we have to select 2 white balls out of 4  white balls ,2 yellow balls out of 6 yellow balls and 2 red balls out of 5 red balls

so number of ways of selecting

[tex]{4 \choose 2} \times {6 \choose 2}\times {5 \choose 2}[/tex]

[tex]=6\times15\times10\\\\=900[/tex]

If bag contains 4 white balls, 6 yellow balls, and 5 red balls then  6 balls can be chosen if there must be 2 balls of each color in 900 ways

To learn more about  combination visit :  https://brainly.com/question/25821700