Answer:
-2 (filled in circle) to 7 (open circle)
Step-by-step explanation:
for the first equation x must be the equal to or smaller than 6. so -3(-2) equals 6 but anything less than -2, let's say -3(-3), will be BIGGER than six, so -2 including -2 which is a filled in circle.
solving it:
-3(x) [tex]\leq[/tex] 6
[tex]\frac{-3x}{-3} \leq \frac{6}{-3}[/tex]
[tex]x\leq -2[/tex]
for the second equation x must be smaller than 17. so first you take out + 3 by subtracting it, leaving the equation as 2x<14. 2(7)<14 is NOT true so anything bigger than 7 leaves it as true because 6.98934747483 can still make it true, so anything smaller than 7 which is 7 with a not filled in, or open, circle
solving it:
[tex]2x + 3 (- 3) < 17 (- 3)[/tex]
2x < 14
[tex]\frac{2x}{2} <\frac{14}{2}[/tex]
x < 7
my explanation is all over the place, but hope this helps!!!
