Answer: 1. 140.9 g Cl
2. 63.58 g O
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given atoms}}{\text {avogadro's number}}[/tex]
1. [tex]\text{Number of moles of Cl}==\frac{2.393\times 10^{24}}{6.023\times 10^{23}}=3.973moles[/tex]
1 mol of Cl weighs = 35.5 g
Thus 3.973 mol of Cl weighs = [tex]\frac{35.5}{1}\times 3.973=140.9g[/tex]
2. [tex]\text{Number of moles of O}==\frac{2.393\times 10^{24}}{6.023\times 10^{23}}=3.973moles[/tex]
1 mol of O weighs = 16 g
Thus 3.973 mol of O weighs = [tex]\frac{16}{1}\times 3.973=63.58g[/tex]
