Answer:
[tex](a)\ A_1 = s^2[/tex]
[tex](b)\ A_2 = 4s^2[/tex]
(c) 4 small squares
Step-by-step explanation:
Given
Small Square:
[tex]Dimension: s[/tex]
Large Square:
[tex]Dimension: 2s[/tex] i.e. twice as long as the small square
Solving (a): The area of the small square.
This is calculated as
[tex]Area = Length^2[/tex]
So, we have:
[tex]A_1 = s^2[/tex]
Solving (b): The area of the large square.
This is calculated as
[tex]Area = Length^2[/tex]
So, we have:
[tex]A_2 = (2s)^2[/tex]
[tex]A_2 = 4s^2[/tex]
Solving (c): Number of small square to cover the large square
To do this, we simply divide their areas.
Let n represents the required number; n is calculated as:
[tex]n = \frac{A_2}{A_1}[/tex]
[tex]n = \frac{4s^2}{s^2}[/tex]
[tex]n = 4[/tex]
Hence, 4 small squares is required to cover the large square
