Answer:
(a) θ₂ = 15.4°
(b) θ₂ = 28.9°
Explanation:
Snell's Law can be written as follows:
[tex]n_1Sin\theta_1 = n_2Sin\theta_2[/tex]
where,
n₁ = incident index
n₂ = refracted index
θ₁ = Angle of incidence
θ₂ = Angle of refraction
(a)
n₁ = incident index = 1
n₂ = refracted index = 2.42
θ₁ = Angle of incidence = 40°
θ₂ = Angle of refraction = ?
Therefore,
[tex](1)(Sin\ 40^o) = (2.42)Sin\theta_2\\\theta_{2} = Sin^{-1}(0.26561)[/tex]
θ₂ = 15.4°
(b)
n₁ = incident index = 1
n₂ = refracted index = 1.33
θ₁ = Angle of incidence = 40°
θ₂ = Angle of refraction = ?
Therefore,
[tex](1)(Sin\ 40^o) = (1.33)Sin\theta_2\\\theta_{2} = Sin^{-1}(0.4832)[/tex]
θ₂ = 28.9°
