I NEED HELP AGAIN PLZ!!!!!
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Answer:
cut the polygon into fourths.
since it's a square, the line values of each of the fourth's lines will equate.
find the area of one of the little triangles first.
area of triangle = 1/2 * a * b
area of triangle = 1/2 * 7 * 7 = 24.5
there're 4 triangles.
24.5*4 = 98
98 yds ^ 2
The area of your square is 98 yd²
The given information about the polygon is half of the diagonal length. Since 7 yds are only half of the diagonal length, we know to add another 7yds to complete the line. Therefore we have 14 as our diagonal length.
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side length a = 9.8994949366117 yd
diagonal q = 14 yd
perimeter P = 39.597979746447 yd
area A = 98 yd²
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Area of a square:
A = a2
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Perimeter of a Square
P = 4a
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Polygon diagonals of a square
q = √(2a2) = a√2
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Side of a Square
a = √A
a = P/4
a = q / √2
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