A thousand dollars is left in bank savings account drawing 7% interest, compounded quarterly for 10 years. What is the balance at the end of that time? show work

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Answer:

Step-by-step explanation:

p(1+r/n)nt

= 1000 (1 + 0.07/4) 4 x 10

1000 (1 + 0.0175) 40

1000(1.0175) 40

1000x 2.0015

= 2001.59

therefore the answer is 2001.59

Compound Interest can be defined as the interest that is compounded on a particular sum of money over a given period of time.

The balance at the end of that time is  $2,001.60

The question wants us to find the balance at the end of that time which means we are to find the amount at the end of 10 years.

The formula for the compound interest is given as:

A = P(1 + r/n)^nt

Where:

A = Amount or the balance after time "t"

Principal(P) = $1,000

Interest rate(R) = 7%

Time(T) = 10 years

First, convert R as a percent to r as a decimal

r = R/100

r = 7/100

r = 0.07 rate per year

Then solve the equation for A

A = P(1 + r/n)^nt

A = 1,000.00(1 + 0.07/4)^(4 x 10)

A = 1,000.00(1 + 0.0175)^(40)

A = $2,001.60

Therefore, the balance at the end of that time is $2,001.60

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