Respuesta :
Answer:
A) Total distance Alf travel during the same amount of time = [tex]\frac{1}{4}s[/tex]
B) Speed of Beth = 4v
Explanation:
Given - Consider two musicians, Alf and Beth. Beth is four times the
distance from the inside of the curve as Alf.
To find - A) Knowing that If Beth travels a distance s during time Δt, how
far does Alf travel during the same amount of time.
B) If Alf moves with speed v, what is Beth's speed?
Proof -
A)
As we know that
Speed = Distance / Time
⇒Distance = Speed ×Time
Now,
Given Speed of Alf = v
⇒Distance of Alf = vt
Also,
Distance of Beth = Speed of beth×time
Given that
Beth is four times the distance from the inside of the curve as Alf. Knowing that If Beth travels a distance s during time Δt, how far does Alf travel during the same amount of time=
⇒Distance of Alf = Speed of Alf×time
= [tex]\frac{1}{4}[/tex] Distance of Beth
⇒Distance of Alf = [tex]\frac{1}{4}s[/tex]
∴ we get
Total distance Alf travel during the same amount of time = [tex]\frac{1}{4}s[/tex]
B)
We know the conversion of angular velocity
ω(Alf) = ω(Beth)
⇒V(Alf)/ r = V(Beth)/4r
⇒V(Alf) = V(Beth) / 4
⇒V(Beth) = 4 V(Alf)
As given, Alf moves with speed v
⇒V(Beth) = 4v
So, the correct option is - a.4v
